Problems on Ages Tricks and Shortcuts For Bank Exams: Problems on ages tricks pdf for bank exams is available in this problems on ages tricks for bank exams article. Problems on ages in one of the most important topics in the quantitative aptitude section of the bank exams. Candidates who are effectively preparing for the upcoming bank exams and other competitive exams shall utilize these problems on ages tricks to be proficient with the problems on ages topic. In most of the bank exams like sbi clerk, sbi po, ibps po, ibps clerk, ibps rrb po, ibps rrb clerk and other insurance exams, problems on ages plays an important role. Problems on ages also asked in various competitive exams like ssc cgl, ssc mts, ssc chsl, railways and more. So candidates should be familiar with the problems on ages tricks to have enough knowledge to know how solve problems on ages questions with the problems on ages formulas and problems on ages tricks simply. If you want to enhance your preparation level on the ages topic by knowing how to solve problems on ages of the aptitude section you have to be familiar with the problems on ages tricks and problems on ages formulas. Problems on ages shortcuts for bank exams will help you to improve your speed and accuracy while solving the problems on ages in the bank exams. We have also provided the problems on ages tricks pdf for bank exams here. You can download this problems on ages tricks pdf for bank exams which is attached in this problems on ages shortcuts for bank exams to solve any type of ages questions easily. 

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Practice problems on ages questions - Free pdf

Problems on Ages Tricks and Shortcuts PDF For Bank Exams

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How to Solve Problems on Ages?

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Problems on Ages Tricks and Shortcuts For Bank Exams

Problems on ages tricks and problems on ages formulas are provided in this problems on ages shortcuts for bank exams article. In bank exams we are required to solve the questions within a time allotted for that question and with accuracy. For that purpose we have added the problems on ages tricks and problems on ages formulas and how to solve the problems on ages questions with these problems on ages tricks and problems on ages formulas. You can exploit these problems on ages tricks and problems on ages formulas to know how to solve problems on ages questions with a limited time and with accuracy. Here you can learn about how to solve the problems on ages easily with speed and more accuracy by using these problems on ages shortcuts and problems on ages formulas. 

• If the present age of a person be X, then

Age after n years = X + n

Age n years ago = X – n

n times the present age = nX

If ages in the numerical are mentioned in the ratio A:B, then A:B will be AX and BX

• If the sum of ages is X and Y and the ratio of their ages is p:q respectively, then you can determine the age of Y by using the formula shown below:

Age of Y = Ratio of Y/ Sum of ratios x sum of ages

Age of Y = q/ (p+q) x A

• After reading the problems on ages, assume the unknown age to be some variable, let say ‘X’
• Convert the statements in the question into mathematical equations.
• If the information in the question comprises ages at different points of time, assume the present age as ‘x’
• If the information in the question comprises ages of different people, assume the age of the youngest person as ‘x’
• Read the question very carefully. The phrase ‘n time more than’ needs to be understood correctly.
• Calculate the variable by solving the equations and the obtained value must satisfy the conditions given in the problem.
• Practice more types of ages on problems questions by using the problems on ages tricks for bank exams is the only way to crack ages questions in the bank exams.
• Before practicing the problems on ages you have to be proficient with the basic concepts of ages problems, problems on ages formulas and problems on ages shortcuts for bank exams. These problems on ages shortcuts will help you to maximise your marks in the forthcoming bank exams and other competitive exams.

Problems on Ages Examples

Example 1:

1) Question: The present ages of the mother and son are 28 and 7 years respectively. If the ratio of their ages will be 11: 4 after x years, then find the value of x.

A.5
B.4
C.6
D.8

Answer:  A

Solution:

(28 + x) / (7 + x) = 11 / 4
112 + 4x = 77 + 11x
35 = 7x
x = 5 

Example 2: 

2) Question: The age of Mathi is 120% of the age of Sunil and the ratio of the age of Sunil to Bala is 5:8. If the age of Mathi 5 years hence is equal to the age of Bala 5 years ago, then find the age of Sunil?

A.25 years
B.50 years
C.20 years
D.30 years 

Answer: A

Solution: 

The ratio of the age of Mathi, Sunil, and Bala =
(5 * 120/100):5:8 = 6:5:8
6x + 5 = 8x – 5
2x = 10
x = 5
The age of Sunil = 5 * 5 = 25 years

Example 3: 

3) Question: The ratio of the age of A 5 years ago to the age of B 4 years hence is 2:5 and the ratio of the present age of B to A is 12:7. Find the sum of the present age of A and B together.

A.39 years
B.65 years
C.57 years
D.45 years 

Answer: C

Solution:

(2x + 5)/(5x – 4) = 7/12
24x + 60 = 35x – 28
11x = 88
x = 8
The present age of A = 2 * 8 + 5 = 16 + 5 = 21 years
The present age of B = 5 * 8 – 4 = 40 – 4 = 36 years
The sum of the present age of A and B together = 21 + 36 = 57 years

Example 4: 

4) Question: Average age of A, B, and C is 30 years. The sum of the present ages of B and C is 85 years. The difference between the present age of A and C is 50 years. Find the average age of B and C together.

A.40.5 years
B.41.5 years
C.42.5 years
D.43.5 years

Answer:

Solution:

C Average age of A,B, and C= 30
A+B+C= 90
Sum of the present age of B and C = 85
Difference between the present age of A and C= 50
The sum of the present age of A and B = 35
A+B+C - A+B= 90- 35 = 55
The present age of C= 55
The present age of B= 85-55= 30
Average age of B and C = (55 + 30)/2= 85/2 = 42.5 years

Example 5: 

5) Question: The present ages of three colleagues are in proportion 3 : 5: 7. Four years ago, the sum of their ages was 48. find thier present ages (in years) ?

A. 12, 20, and 28 years

B. 14, 24, and 28 years

C. 14, 28, and 30 years

D. 14, 26, and 28 years

Answer: A

Solution: 

Let the present age of three colleagues are:   3x, 5x and 7x

(3x – 4) + (5x – 4) + (7x – 4) = 48.

15x – 12 = 48 ⇒ 15x = 60 ⇒ x = 4.

Their present ages are 12 years, 20 years, and 28 years respectively.

Hence, option A is correct.

Example 6: 

6) Question: Abhi’s age after six years will be three-seventh of his father’s age. Ten years ago, the ratio of their ages was 1: 5. What is Abhi’s father’s age at present?

A. 50 years

B. 40 years

C. 35 years

D. 30 years

Answer: A

Solution: 

Let the ages of Abhi and his father 10 years ago be x and 5x years respectively. Then, Abhi’s age after 6 years = (x + 10) + 6 = (x + 16) years. 

Father’s age after 6 years = (5x + 10) + 6 = (5x + 16) years.

Therefore, (x+16) = 3/7(5x+16)

7 (x + 16) = 3 (5x + 16) ⇒ 7x + 112 = 15x + 48

8x =64, x = 8.

Hence, Abhi’s father’s present age = (5x + 10) = 50 years.

Example 7: 

7) Question: One year ago, the ratio of Gaurvi and Sachin’s ages was 6: 7, respectively. Four years hence, the ratio would be 7: 8. How old is Sachin? 

A. 35 years

B. 36 years

C. 32 years

D. 28 years

Answer: B

Solution:

Let Gaurvi and Sachin’s ages are 6x and 7x years, respectively. Then, Gaurvi’s age is 4 years hence = (6x + 1) + 4 = (6x + 5) years.

Sachin’s age is 4 years hence = (7x + 1) + 4 = (7x + 5) years.

6x + 5/ 7x+5= 7 /8

8 (6x + 5) = 7 (7x + 5) ⇒ 48x + 40 = 49x +35 x = 5,

Hence, Sachin’s present age = (7x + 1) = 36 years.

Example 8: 

8) Question: Sanat is 20 years old while Sumit is 25 years old. After how many years the ratio of their age will be 7:8?

A. 15 years
B. 10 years
C. 20 years
D. 25 years

Answer: A

Solution:
Let the years be x.
According to the given condition,
(Sanat + x) / (Sumit + x) = 7 / 8 ………..(1)
On solving we get,
x = 15 years

Example 9: 

9) Question: 2 years ago the ratio of ages A, B, and C was 2 : 3 : 4 and the sum of their present age was 60 then find the present age of B.
a) 18 years
b) 20 years
c) 21 years
d) 24 years 

Answer: B
Solution:
A^-2: B^-2:C^-2 = 2 : 3 : 4 …………..(1)
A + B + C = 60……………..(2)
Sum before 2 years = 54 years…….(3)
9 units = 54 years
1 unit = 6 years
The present age of B = 20 years

Example 10: 

10) Question: The sum of the ages of three persons A, B and C is 60 years. A is 5 years elder than B who is 6 years younger than C. Find the present age of B.
a) 49/3 years
b) 48 years
c) 14 years
d) None of these

Answer: A

Solution:

A = B + 5 ………..(1)
B = C - 6 ………..(2)
A + B + C = 60 years………(3)
Solving the above equations,
B = 49/3 years

We hope that these problems on ages tricks and problems on ages shortcuts article will be useful to your bank exams preparation. By exploiting these problems on ages tricks and problems on ages shortcuts you can find how to solve problems on ages in various types and you will be familiar with the problems on ages formulas. So that you can follow our guidely team to know various information and study materials regarding bank exams preparation. 

Problems on Ages Tricks and Shortcuts For Bank Exams FAQs

Q. What are the basic concepts to find the age of a person?

A. If the present age of a person be X, then

Age after n years = X + n

Age n years ago = X – n

n times the present age = nX

If ages in the numerical are mentioned in the ratio A:B, then A:B will be AX and BX

Q. What is the Problems on Ages?

A. The Problems on Ages is based on your ability to handle the linear equation. There are some situations in which the ages of two or more persons are compared with the ratio, fraction or percentage.