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Quadratic Equation Practice Problems
1) Question:
I) x2+5x-176=0
II) y2-9y-162=0
Options:
A) x=(-15,11), y= (18,-10)
B) x = y or the relationship can’t be determined
C) x=(-16,11), y= (18,-9)
D) x=(-15,13), y= (17,-10)
Answer: (B)
Solution:
x2+5x-176=0
x2+16x-11x-176=0
x(x+16)-11(x+16)=0
(x+16) (x-11)=0
x= -16,11
y2-9y-162=0
y2-18y+9y-162=0
y(y-18)+9(y-18)=0
(y-18) (y+9)=0
y= 18,-9
Therefore relationship can’t be established.
2) Question:
I) x2+6x+9=0
II) 2y2+13y+21=0
Options:
A) x < y
B) x ≥ y
C) can’t be determined
D) x<=y
Answer: (B)
Solution:
x2+6x+9=0
x2+ 3x + 3x + 9 = 0
x(x + 3) + 3(x + 3) =0
(x + 3) (x + 3) = 0
x=-3, -3
2y2+13y+21=0
2y2+6y+7y+21=0
2y(y+3) +7(y+3) =0
(y+3) (2y+7) =0
y= -3, -3.5
Therefore x ≥ y
3) Question:
I) 3x2-13x+10=0
II) y2-22y+120=0
Solution:
3x2-13x+10=0
3x2-3x-10x+10 =0
3x(x-1) - 10(x-1)=0
(x-1) (3x-10)=0
x=1, 3.33
y2-22y+120=0
y2-10y-12y+120=0
y(y-10) -12(y-10)=0
(y-10) (y-12)=0
y=10,12
Therefore x < y
Answer: x < y
4) Question:
I) 3x2-7x+4=0
II) 2y2-9y+10=0
Solution:
3x2-7x+4=0
3x2-3x-4x+4=03x(x-1) -4(x-1)=0
(x-1) (3x-4) =0
x= 1, 1.33
2y2-9y+10=0
2y2-4y-5y+10=0
2y(y-2) -5(y-2)=0
(y-2) (2y-5)=0
y= 2, 2.5
Therefore x < y
Answer: x < y
5) Question:
I) (x+8)2=36x-32
II) (y-12)2=6y-81
Solution:
(x+8)2=36x-32
(x2+16x+64) =36x -32
x2-20x+96=0x2-12x-8x+96=0
x(x-12) -8(x-12)=0(x-12) (x-8) =0
x=12,8
(y-12)=6y-81
y2-24y+144-6y+81=0
y2-30y+225=0
y2– 15y – 15y + 225 = 0
y(y – 15) – 15(y – 15) = 0
(y-15)2=0
y=15, 15
Therefore x < y
Answer: x < y
6) Question:
I) x2- 4x – 21 = 0
II). y2- 8y +16 = 0
Solution:
x2- 4x – 21 = 0
(x – 7) (x + 3) = 0
X = 7, -3
y2-8y +16 = 0
(y - 4) (y – 4) = 0
Y = 4, 4
Answer: Can’t be determined
7) Question:
I) 2x2+ 13x + 21 = 0
II) 3y2+ 4y – 15 = 0
Solution:
2x2+ 13x + 21 = 0
2x2+ 6x + 7x + 21 = 0
2x (x + 3) + 7(x + 3) = 0
(2x + 7) (x + 3) = 0
x = -7/2, -3 =
x = -3.5, -3
3y2+ 4y – 15 = 0
3y2+ 9y - 5y – 15 = 0
3y (y + 3) -5(y + 3) = 0
(3y – 5) (y + 3) = 0
y = 5/3, -3 = 1.667, -3
x ≤ y
Answer: x ≤ y
8) Question:
I) 2x2- 19x + 35 =0
II) 2y2- 13y + 21 =0
Solution:
2x2 - 19x + 35 =0
2x2 - 14x - 5x + 35 =0
2x(x - 7) - 5(x - 7) =0
(2x - 5)(x - 7) =0
x=7, 2.5
2y2 - 13y + 21 =0
2y2 - 6y - 7y + 21 =02y(y - 3) - 7(y - 3) =0
(2y - 7)(y - 3) =0
y=3, 3.5
Hence the relationship between x and y cannot be established.
Answer: the relationship between x and y cannot be established.
9) Question:
I) 4x2– 17x + 18 = 0
II) 3y2– 29y + 56 = 0
Solution:
4x2– 17x + 18 = 0
=>4x2 – 8x – 9x + 18 = 0
=>4x (x – 2) – 9 (x – 2) = 0
=>(4x – 9) (x – 2) = 0
=> x = 9/4, 2
3y2 – 29y + 56 = 0
=>3y2 –21y – 8y + 56 = 0
=> 3y (y – 7) – 8 (y – 7) = 0
=> (3y – 8) (y – 7) = 0
=> y = 8/3, 7
Hence, x < y
Answer: x < y
10) Question:
I).x2+18x=144
II).3y2+19y+26=0
Solution:
x2+18x-144=0
x2+ 24x – 6x – 144 = 0
x(x + 24) – 6(x + 24) = 0
(x-6) (x+24)=0
x= 6, -24
3y2+19y+26=0
3y2+ 13y + 6y + 26 = 0
y(3y + 13) + 2(3y + 13) = 0
(y+2) (3y+13) =0
y= -2, -4.33
Relationship can’t be established
Answer: The relationship cannot be established.
Click Here To Practice More Quadratic Equation Problems - Free PDF
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